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What keyword should I enter to create an object ''pesto_pasta'' of type Recipe?
let pesto_pasta =? (('pasta', 500, 'g'), ('pesto', 100, 'g'));
0
Community Evaluations
Dragon parfait
30/07/2024
Y'a un gros problĂšme de traduction
Afonso
06/04/2023
To create an object pesto_pasta of type Recipe, you need to use the new keyword followed by the name of the constructor function Recipe.
Auteur anonyme
19/07/2024
La bonne réponse est alors la réponse 2?
Si c'est cela il y a un problÚme car j'ai indiqué la réponse 2 et on me dit mauvaise réponse
Incorrect answer
Luke Farrell30/07/2024
Requires new Class - this is an incorrect answer.
Incorrect answer
Auteur anonyme20/07/2024
incorrect anwser,its new recipe
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