Expert
What will the following pseudo-code display?
class A
{
public function foobar() {
echo this->foo();
echo this->bar();
}
private function foo() {
return "A::foo\\n";
}
public function bar() {
echo "A::bar\\n";
}
}
class B extends A
{
private function foo() {
return "B::foo\\n";
}
public function bar() {
echo "B::bar\\n";
}
}
var toto = new B();
toto->foobar();
Author: Eric HostaleryStatus: PublishedQuestion passed 1307 times
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Community Evaluations
Najmul
01/10/2023
The provided pseudo-code contains some syntax errors, such as the use of 'this' instead of '$this' to refer to object properties and methods.
In this code, class B overrides the foo() method while extending class A, and it also overrides the bar() method. When you create an instance of class B and call its foobar() method, it calls the overridden foo() and bar() methods from class B.
I think the answer is:
B::foo
B::bar
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